我想要华东师大版九年级下册数学23章一元二次方程所有的课件，包括23.1一元二次方程、23.2一元二次方程的
1)x^2-9x+8=0 答案：x1=8 x2=1 (2)x^2+6x-27=0 答案：x1=3 x2=-9 (3)x^2-2x-80=0 答案：x1=-8 x2=10 (4)x^2+10x-200=0 答案：x1=-20 x2=10 (5)x^2-20x+96=0 答案：x1=12 x2=8 (6)x^2+23x+76=0 答案：x1=-19 x2=-4 (7)x^2-25x+154=0 答案：x1=14 x2=11 (8)x^2-12x-108=0 答案：x1=-6 x2=18 (9)x^2+4x-252=0 答案：x1=14 x2=-18 (10)x^2-11x-102=0 答案：x1=17 x2=-6 (11)x^2+15x-54=0 答案：x1=-18 x2=3 (12)x^2+11x+18=0 答案：x1=-2 x2=-9 (13)x^2-9x+20=0 答案：x1=4 x2=5 (14)x^2+19x+90=0 答案：x1=-10 x2=-9 (15)x^2-25x+156=0 答案：x1=13 x2=12 (16)x^2-22x+57=0 答案：x1=3 x2=19 (17)x^2-5x-176=0 答案：x1=16 x2=-11 (18)x^2-26x+133=0 答案：x1=7 x2=19 (19)x^2+10x-11=0 答案：x1=-11 x2=1 (20)x^2-3x-304=0 答案：x1=-16 x2=19 (21)x^2+13x-140=0 答案：x1=7 x2=-20 (22)x^2+13x-48=0 答案：x1=3 x2=-16 (23)x^2+5x-176=0 答案：x1=-16 x2=11 (24)x^2+28x+171=0 答案：x1=-9 x2=-19 (25)x^2+14x+45=0 答案：x1=-9 x2=-5 (26)x^2-9x-136=0 答案：x1=-8 x2=17 (27)x^2-15x-76=0 答案：x1=19 x2=-4 (28)x^2+23x+126=0 答案：x1=-9 x2=-14 (29)x^2+9x-70=0 答案：x1=-14 x2=5 (30)x^2-1x-56=0 答案：x1=8 x2=-7 (31)x^2+7x-60=0 答案：x1=5 x2=-12 (32)x^2+10x-39=0 答案：x1=-13 x2=3 (33)x^2+19x+34=0 答案：x1=-17 x2=-2 (34)x^2-6x-160=0 答案：x1=16 x2=-10 (35)x^2-6x-55=0 答案：x1=11 x2=-5 (36)x^2-7x-144=0 答案：x1=-9 x2=16 (37)x^2+20x+51=0 答案：x1=-3 x2=-17 (38)x^2-9x+14=0 答案：x1=2 x2=7 (39)x^2-29x+208=0 答案：x1=16 x2=13 (40)x^2+19x-20=0 答案：x1=-20 x2=1 (41)x^2-13x-48=0 答案：x1=16 x2=-3 (42)x^2+10x+24=0 答案：x1=-6 x2=-4 (43)x^2+28x+180=0 答案：x1=-10 x2=-18 (44)x^2-8x-209=0 答案：x1=-11 x2=19 (45)x^2+23x+90=0 答案：x1=-18 x2=-5 (46)x^2+7x+6=0 答案：x1=-6 x2=-1 (47)x^2+16x+28=0 答案：x1=-14 x2=-2 (48)x^2+5x-50=0 答案：x1=-10 x2=5 (49)x^2+13x-14=0 答案：x1=1 x2=-14 (50)x^2-23x+102=0 答案：x1=17 x2=6 (51)x^2+5x-176=0 答案：x1=-16 x2=11 (52)x^2-8x-20=0 答案：x1=-2 x2=10 (53)x^2-16x+39=0 答案：x1=3 x2=13 (54)x^2+32x+240=0 答案：x1=-20 x2=-12 (55)x^2+34x+288=0 答案：x1=-18 x2=-16 (56)x^2+22x+105=0 答案：x1=-7 x2=-15 (57)x^2+19x-20=0 答案：x1=-20 x2=1 (58)x^2-7x+6=0 答案：x1=6 x2=1 (59)x^2+4x-221=0 答案：x1=13 x2=-17 (60)x^2+6x-91=0 答案：x1=-13 x2=7提问者评价xiexie+15因为具有相同实根,所以不妨设这个实根为m所以m²+2Am+B²=0......(1)式,m²+2Cm-B²=0......(2)式(1)-(2)2(A-C)m+2B²=0,∴m=B²/(A-C)(1)+(2)2m²+2(A+C)m=0,∴m=0或者m=-A-C因为m是唯一的,又因为B²≠0所以m=B²/(A-C)=-A-C,即B²=C²-A²,即A²+B²=C²所以A,B,C为直角三角形的三边
